Derivative & integral table

Detivative table

y=c        y′=0y=ax        y′=axln⁡ay=log⁡ax        y′=1xln⁡ay=ln⁡x        y′=1xy=xa        y′=axa−1y=sin⁡x        y′=cos⁡xy=cos⁡x        y′=−sin⁡xy=tan⁡x        y′=sec⁡2xy=cot⁡x        y′=−csc⁡2xy=arcsin⁡x        y′=11−x2y=arccos⁡x        y′=−11−x2y=arctan⁡x        y′=11+x2y=arccotx        y′=−11+x2\begin{aligned} y = c \ \ \ \ &\ \ \ \ y' = 0\\ y = a^x \ \ \ \ &\ \ \ \ y' = a^x \ln a\\ y = \log_a x \ \ \ \ &\ \ \ \ y' = \frac{1}{x\ln a}\\ y = \ln x \ \ \ \ &\ \ \ \ y' = \frac{1}{x}\\ y = x^a \ \ \ \ &\ \ \ \ y' = ax^{a-1}\\ y = \sin x \ \ \ \ &\ \ \ \ y' = \cos x\\ y = \cos x \ \ \ \ &\ \ \ \ y' = -\sin x\\ y = \tan x \ \ \ \ &\ \ \ \ y' = \sec^2 x\\ y = \cot x \ \ \ \ &\ \ \ \ y' = -\csc^2 x\\ y = \arcsin x \ \ \ \ &\ \ \ \ y' = \frac{1}{\sqrt{1-x^2}}\\ y = \arccos x \ \ \ \ &\ \ \ \ y' = -\frac{1}{\sqrt{1-x^2}}\\ y = \arctan x \ \ \ \ &\ \ \ \ y' = \frac{1}{1+x^2}\\ y = \mathrm{arccot} x \ \ \ \ &\ \ \ \ y' = -\frac{1}{1+x^2} \end{aligned}

积分表

∫kdx=kx∫xadx=1a+1xa+1(a≠−1)  ∫1xdx=ln⁡∣x∣∫axdx=axln⁡a(0<a≠1)∫exdx=ex∫sin⁡xdx=−cos⁡x∫cos⁡xdx=sin⁡x∫sec⁡2xdx=tan⁡x∫csc⁡2xdx=−cot⁡x∫dxa2+x2=1aarctan⁡xa(a≠0)∫dxx2−a2=12aln⁡∣x−ax+a∣(a≠0)∫dxa2−x2=arcsin⁡xa(a>0)∫dxx2±a2=ln⁡∣x±x2±a2∣\begin{aligned} & \int k\mathrm{d}x = kx\\ & \int x^a \mathrm{d}x = \frac{1}{a+1} x^{a+1} &(a\neq -1) \ \ \\ & \int \frac{1}{x} \mathrm{d}x = \ln \lvert x\rvert \\ & \int a^x \mathrm{d}x = \frac{a^x}{\ln a} &(0 < a \neq 1)\\ & \int e^x \mathrm{d}x = e^x\\ & \int \sin x \mathrm{d}x = -\cos x \\ & \int \cos x \mathrm{d}x = \sin x\\ & \int \sec^2x \mathrm{d}x = \tan x\\ & \int \csc^2 x\mathrm{d}x = -\cot x \\ & \int \frac{\mathrm{d}x}{a^2 + x^2} = \frac{1}{a} \arctan \frac{x}{a} & (a\neq 0)\\ & \int \frac{\mathrm{d}x}{x^2 - a^2} = \frac{1}{2a}\ln \left\lvert \frac{x-a}{x+a} \right\rvert & (a\neq 0)\\ & \int \frac{\mathrm{d}x}{\sqrt{a^2 - x^2}} = \arcsin \frac{x}{a} & (a>0) \\ & \int \frac{\mathrm{d}x}{\sqrt{x^2 \pm a^2 }} = \ln \left\lvert x \pm \sqrt{x^2 \pm a^2} \right\rvert \end{aligned}

Snippets

∫eaxdx=1aeax\int{e^{ax}}\mathrm{d}x = \frac{1}{a} e^{ax}

Taylor expansion

f(x)=f(a)+f′(a)(x−a)+f′′(a)2!(x−a)2+f3(a)3!(x−a)3+⋯+fn(a)n!(x−a)n+⋯f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)}{2!}(x-a)^2 + \frac{f^3(a)}{3!}(x-a)^3 + \cdots + \frac{f^n(a)}{n!}(x-a)^n + \cdots

For example,

ex=1+x1!+x22!+x33!+⋯e^{x} = 1 + \frac{x}{1!} + \frac{x^2}{2!} + \frac{x^3}{3!} + \cdots

cos⁡(x)=1−x22!+x44!−x66!+⋯\cos(x) = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{6!} + \cdots

sin⁡(x)=x−x33!+x55!−x77!+⋯\sin(x) = x - \frac{x^3}{3!} + \frac{x^5}{5!} - \frac{x^7}{7!} + \cdots

积化和差 和差化积

sin(α)cos(β)=sin(α+β)+sin(α−β)2cos(α)sin(β)=sin(α+β)−sin(α−β)2cos(α)cos(β)=cos(α+β)+cos(α−β)2sin(α)sin(β)=−cos(α+β)−cos(α−β)2\begin{aligned} sin(\alpha) cos(\beta) &= \frac{ sin(\alpha + \beta) + sin(\alpha - \beta) }{2}\\ cos(\alpha) sin(\beta) &= \frac{sin(\alpha + \beta) - sin(\alpha - \beta)}{2}\\ cos(\alpha) cos(\beta) &= \frac{cos(\alpha + \beta) + cos(\alpha - \beta)}{2}\\ sin(\alpha) sin(\beta) &= - \frac{cos(\alpha + \beta) - cos(\alpha - \beta)}{2} \end{aligned}

sin(α)+sin(β)=2sin(α+β2)cos(α−β2)sin(α)−sin(β)=2cos(α+β2)sin(α−β2)cos(α)+cos(β)=2cos(α+β2)cos(α−β2)cos(α)−cos(β)=−2sin(α+β2)sin(α−β2)\begin{aligned} sin(\alpha) + sin(\beta) &= 2 sin(\frac{\alpha + \beta}{2}) cos(\frac{\alpha - \beta}{2})\\ sin(\alpha) - sin(\beta) &= 2 cos(\frac{\alpha + \beta}{2}) sin (\frac{\alpha - \beta}{2})\\ cos(\alpha) + cos(\beta) &= 2 cos(\frac{\alpha + \beta}{2}) cos (\frac{\alpha - \beta}{2})\\ cos(\alpha) - cos(\beta) &= -2sin(\frac{\alpha + \beta}{2}) sin (\frac{\alpha - \beta}{2}) \end{aligned}


Derivative & integral table
https://www.billhu.us/2022/11_d/
Author
Bill Hu
Posted on
January 16, 2022
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